Let's have a servo block to detect the position and feedback that before Fv/m with a constant "Alpha".

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"Alpha" to feedback the position is "1.0". By the way, look at the block diagram carefully. "AlphaFv/m" is located just parallel for "K/m"!! i.e. (K+AlphaFv)/m has become much larger than K/m. The feedback made the spring "very stiff".
The displacement has become as small as 1um as the frequency response says. However, still "Q" is high and it's unstable...
Quiz 2
How does the pickup follow the displacement as time goes on?? Hint: You can choose "Step-Res" for the list box on the applet. Here is the answer.

See how to decrease the resonance

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